2[t-(2t+16)+14]=2(2+4)

Solution for 2[t-(2t+16)+14]=2(2+4) equation:

Simplifying
2[t + -1(2t + 16) + 14] = 2(2 + 4)

Reorder the terms:
2[t + -1(16 + 2t) + 14] = 2(2 + 4)
2[t + (16 * -1 + 2t * -1) + 14] = 2(2 + 4)
2[t + (-16 + -2t) + 14] = 2(2 + 4)

Reorder the terms:
2[-16 + 14 + t + -2t] = 2(2 + 4)

Combine like terms: -16 + 14 = -2
2[-2 + t + -2t] = 2(2 + 4)

Combine like terms: t + -2t = -1t
2[-2 + -1t] = 2(2 + 4)
[-2 * 2 + -1t * 2] = 2(2 + 4)
[-4 + -2t] = 2(2 + 4)

Combine like terms: 2 + 4 = 6
-4 + -2t = 2(6)

Multiply 2 * 6
-4 + -2t = 12

Solving
-4 + -2t = 12

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -2t = 12 + 4

Combine like terms: -4 + 4 = 0
0 + -2t = 12 + 4
-2t = 12 + 4

Combine like terms: 12 + 4 = 16
-2t = 16

Divide each side by '-2'.
t = -8

Simplifying
t = -8